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And talking of update operators, let me now point out that, logically speaking, only one such operator is needed: namely, the assignment operator. All other update operators are really just shorthand for some assignment. (I ll spell this point out in detail in connection with the relational update operators in particular in the section Relation Values and Variables, later.) Since we already know that to say something s a variable is to say it s updatable, no more and no less, it follows that to say something s a variable is to say it s assignable to, no more and no less. In other words, to say that V is a variable is to say, precisely, that the following assignment is legal: V := v ; (where v is a value of the same type as V). Of course, v can be denoted by an arbitrary expression of the appropriate type; thus, the assignment operation takes the general syntactic form LHS := RHS ; where LHS is a variable reference, denoting some variable V of some type T, and RHS is an arbitrary expression of that same type T denoting a value v also of that type T. Note: Actually the syntactic form just shown for the assignment operator is not the most general. In The Third Manifesto, Hugh Darwen and I require support for a more general form that we call multiple assignment, which allows several variables to be updated at the same time (I m speaking pretty loosely here!). Multiple assignment is discussed in detail in 11; for the remainder of the present chapter, I ll limit my attention to assignments of the simple (or single ) form already discussed.

If you are not interested in volunteering your time to help others, then perhaps you have an overlapping hobby that allows for a learning opportunity. In my case, I love Fantasy Football. Years ago I helped build a custom web site with a database back end. This gave me lots of learning opportunities that helped me when I got my initial opportunity to become a DBA. Still another way for you to get prepared is to look online for part-time help. You may find someone that is willing to offer some contract work to help out with a database during nights and weekends. Such positions do exist, even for people with little to no experience. In most cases, they can directly lead to junior DBA roles. I would caution you to stay away from job advertisements that seem too good to be true; they usually are.

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Consider the following simple example: VAR VC CHAR ; VC := 'Middle' ; SUBSTR ( VC, 2, 1 ) := 'u' ; After the first assignment here, the variable VC has the value Middle ; after the second, it has the value Muddle the effect of this latter assignment is to zap the second character position within that variable, replacing the i by a u. Note in particular that the left side of that second assignment does not consist of a simple variable reference. So is it really true that assignments always take the specific syntactic form shown in the previous section Well, yes, fundamentally it is true. The second assignment in the foregoing example is really shorthand for the following longer one: VC := SUBSTR ( VC, 1, 1 ) || 'u' || SUBSTR ( VC, 3, 4 ) ; Now the left side is a simple variable reference, as required. As for the right side, the expression on that side denotes the character string obtained by concatenating, in left-to-right order, the first character of the current value of VC, the character u , and the last four characters of the current value of VC. It follows that the overall assignment has exactly the effect previously explained.

If you want to add your own steps to this list, you can do something like the following: <PropertyGroup> <TeamBuildDependsOn> CustomBeforeTeamBuild; $(TeamBuildDependsOn); CustomAfterTeamBuild; </TeamBuildDependsOn> </PropertyGroup> <Target Name="CustomBeforeTeamBuild"> <Message Importance="normal" Text="This is BEFORE the TeamBuild target gets invoked"/> </Target>.

Here s another example: VAR VA ARRAY INTEGER ; VA := ARRAY ( 1, 2, 3, 4, 5 ) ; VA[4] := 0 ; After the first assignment, the variable VA has as its value an array of five integers, with the ith array element equal to i (i = 1, 2, 3, 4, 5); after the second assignment, the fourth element is 0 instead of 4, while the others remain unchanged Again, the left side of the latter assignment isn t just a simple variable reference; again, however, the assignment is really just shorthand for another one in which the left side is such a variable reference Here s the expanded version: VA := ARRAY ( VA[1], VA[2], VA[3], 0, VA[5] ) ; Note: The expression on the right side here is an array selector invocation (The same remark applies to the earlier assignment to VA also, of course.

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